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0=325x-7500-x^2
We move all terms to the left:
0-(325x-7500-x^2)=0
We add all the numbers together, and all the variables
-(325x-7500-x^2)=0
We get rid of parentheses
x^2-325x+7500=0
a = 1; b = -325; c = +7500;
Δ = b2-4ac
Δ = -3252-4·1·7500
Δ = 75625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{75625}=275$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-325)-275}{2*1}=\frac{50}{2} =25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-325)+275}{2*1}=\frac{600}{2} =300 $
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